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- µ@WeightingScore 6, 3,1,1
- @atGraphic 5,12
- @Picture algebra\a010101.bmp
- @at 68,5
- Have a look at the following number
- pattern.
- @at ,+5
- 2, 4, 8, 16, 32, 64, 128, 256
- @at 5,+10
- @InputWidth 25
-
-
- What is the value of the next term? #[N]_
- @answer 1,512
- @Feedback 0,?
- No, to find the next number you need to multiply
- the last number by 2. 256 ╫ 2 = 512.
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-
-
-
-
-
-
- @question
- Use the words below to make up the rule
- for this number pattern.
- @at ,+8
- @InputWidth 53
- Rule :#^#[A] the #[A] by #[A]_
- #tto find the #[A]._
-
- #Alast╛term# #Amultiply# #A2# #Anext╛term#_
- @Answer 4,multiply,last╛term,2,next╛term
- @Feedback E1,?,?,?,?
- No, the complete rule is :
- multiply the last term by 2 to find the next term.
- @Feedback 0,?,?,?,?
- No, the complete rule is :
- multiply the last term by 2 to find the next term.
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-
-
-
-
- @question
- @at ,+8
- Using the same rule but a different starting
- number, the third number is 12.
- @at ,+8
- What is the starting number? #[N]
- @Answer 1,3
- @Feedback 0,?
- No, you should divide the number
- 12 by 2 twice to find the first number.
- 12 ≈ 2 = 6, then 6 ≈ 2 = 3. The
- starting number is 3.
- @Feedback 1
- Well done, the third number is 12
- so divide it by 2 twice to find the
- starting number.
-
- .
- number.
-
- umber.
- r.
-